好的哦 1100的素數(shù)可以這樣編程： python def is_prime(num): if num <= 1: return False for i in range(2, int(num0.5)+1): if num % i == 0: return False return True
primes = [i for i in range(2, 1101) if is_prime(i)] print(primes)

python def is_prime(num): if num <= 1: return False for i in range(2, int(num0.5) + 1): if num % i == 0: return False return True
primes = [num for num in range(2, 1101) if is_prime(num)] print(primes)

python def is_prime(num): if num < 2: return False for i in range(2, int(num0.5) + 1): if num % i == 0: return False return True
prime_numbers = [x for x in range(1100) if is_prime(x)] print(prime_numbers)

使用for循環(huán)和sqrt函數(shù)可以編寫程序找出1100以內(nèi)的素數(shù)循環(huán)遍歷數(shù)字，使用sqrt優(yōu)化判斷是否為素數(shù)過程。